What's a?!

Algebra Level pending

24 x 2 + 25 x 47 a x 2 = 8 x 3 53 a x 2 \frac{ 24x^2+25x-47}{ax-2} =-8x-3-\frac{53}{ax-2}

The equation above, where a a is a constant, holds true for all values of x 2 a x \ne \dfrac 2a . What is the value of a a ?

3 3 16 -16 16 16 3 -3

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

2 solutions

Chew-Seong Cheong
Apr 19, 2020

24 x 2 + 25 x 47 a x 2 = 8 x 3 53 a x 2 = 8 a x 2 + ( 16 3 a ) x + 6 53 a x 2 \begin{aligned} \frac {24x^2+25x-47}{ax-2} & = -8x-3-\frac {53}{ax-2} \\ & = \frac {-8ax^2 + (16-3a)x + 6 - 53}{ax-2} \end{aligned}

Equating the coefficient of x 2 x^2 on both sides, we have 8 a = 24 a = 3 -8a = 24 \implies a = - 3 . Note that 16 3 a = 25 16-3a = 25 . Therefore, a = 3 a=\boxed{-3} .

Same explanation, so I'm not going to write it. Great work!

Mahdi Raza - 1 year, 1 month ago

Log in to reply

Thanks, can you upvote?

Chew-Seong Cheong - 1 year, 1 month ago

Log in to reply

Sure, done

Mahdi Raza - 1 year, 1 month ago

Very well, I am impressed!

Muhammad Mustafa Ahmad - 1 year, 1 month ago

ANSWER EXPLANATION: There are two ways to solve this question. The faster way is to multiply each side of the given equation by a x 2 ax-2 (so you can get rid of the fraction). When you multiply each side by a x 2 ax-2 , you should have:

24 x 2 + 25 x 47 = ( 8 x 3 ) ( a x 2 ) 53 24x2+25x-47=(-8x-3)(ax-2)-53

You should then multiply ( 8 x 3 ) (-8x-3) and (ax−2) using FOIL.

24 x 2 + 25 x 47 = 8 a x 2 3 a x + 16 x + 6 53 24x2+25x-47=-8ax2-3ax+16x+6-53

Then, reduce on the right side of the equation

24 x 2 + 25 x 47 = 8 a x 2 3 a x + 16 x 47 24x2+25x-47=-8ax2-3ax+16x-47

Since the coefficients of the x 2 x2 -term have to be equal on both sides of the equation, 8 a = 24 -8a=24 , or a = 3 a=-3 .

The final answer is B.

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...