What's inside it?

Geometry Level 3

Find the number of integral points in the interior of the triangle having vertices ( 0 , 0 ) , ( 21 , 0 ) (0,0),(21,0) and ( 0 , 21 ) (0,21) .


The answer is 190.

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1 solution

Abhay Tiwari
Apr 26, 2016

Let us first consider for a smaller square(let's say for triangle having co-ordinates: ( 0 , 0 ) , ( 0 , 5 ) a n d ( 5 , 0 ) (0,0), (0, 5) and (5,0) )

We observe that there are a total of ( n 2 ) ( n 1 ) 2 = 6 \frac{(n-2)(n-1)}{2}=\boxed{6} integral points, let us call this equation 1 1

now we know the pattern and the foramula required then it can easily be done for ( 0 , 0 ) , ( 0 , 21 ) a n d ( 21 , 0 ) (0,0), (0, 21) and (21,0)

substituting n = 21 n=21 in 1 1

we get: ( 19 ) ( 20 ) 2 = 190 \frac{(19)(20)}{2}=\boxed{190}

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