what's next?

This is not really a problem, more like trick question.

$1$ st seq. : $0$ (given).

$2$ nd seq. : there is a $1$ number $0$ in the last seq., so it's $10$ .

$3$ rd seq. : there is a $1$ number $1$ and $1$ number $0$ in the last seq., so it's $1110$

$4$ th seq. : there is $3$ number $1$ and $1$ number $0$ in the last seq., so it's $3110$ .

And so on.

In my humble opinion, this problem isn't really challenging, it would be if you ask the $n$ -th term, such as 100.