∫ − π π ( x 2 + 5 ) ( 7 − cos 4 x ) x 4 ( sin 5 x − sin 3 x − 2 x ) d x = ?
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The first thing I wondered when I saw the function was that why was it in Level 2 with just mere 40 points to score. That exact moment I saw the limits and knew what such a clever integral was hiding within itself!
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I originally posted it in the Hard section because I wanted to make people sweat a little first :)
If there is a polynomial P , then you should prove that ∫ − a a P d x = 0 .
Let P to a polynomial.
Then, ∫ − a a P d x = 0 .
You dont have to expand those polynomials.
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The function given is odd . hence its integral from -a to a would be zero