What's their relation ?

Algebra Level 3

Over all real numbers x x , what is the relation between sin ( cos ( x ) ) \sin( \cos(x)) and cos ( sin ( x ) ) \cos(\sin(x)) ?

cos(sin(x)) <= sin(cos(x)) cos(sin(x)) < sin(cos(x)) cos(sin(x)) > sin(cos(x)) cos(sin(x)) >= sin(cos(x))

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1 solution

We can have multiple procedures, but it seems that most of us are adsorbent to this way:

As we know, RANGE of sin x \sin x and cos x \cos x functions are [ 1 , 1 ] [-1,1] , which will now be our RESTRICTED DOMAIN for the latter imposed sin \sin & cos \cos functions.

Simply, we derive, where sin ( cos ( x ) ) \sin(\cos(x)) function will range some value around 0 0 , cos ( sin ( x ) ) \cos(\sin(x)) function will range around and similarly close to 1 1 .

So, there remains 0 0 probability of the functions being equal, and we come up the decision that, sin ( cos ( x ) ) < cos ( sin ( x ) ) \sin(\cos(x))<\cos(\sin(x)) .

That's all!

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