Plates are arranged as shown in the figure such that the effective area between each of them is and the effective distance between each pair of neighboring plates is . What is the net capacitance between the terminals A and B ?
Clarification : is the permittivity of free space.
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The given plates can be taken as a set of capacitors and arranged as shown above
The points 1 , 2 and 3 , 4 are at same potential. Hence the the circuit becomes as follows:
The above circuit represents a Wheatstone bridge. Hence the capacitor marked as C becomes ineffective .
∴ The net capacitance, C e f f is
C e f f = ( C + C ) ∣ ∣ ( C + C ) = 2 2 C = C where C = d ϵ 0 A
∴ C = d ϵ 0 A