A roulette wheel contains 38 numbers of which 18 are red, 18 are black and 2 are green. When the roulette ball is spun, it is equally likely to land on any of the 38 numbers. In two plays at the wheel, what is the probability that the ball lands on black both times? Express your answer in % upto two decimal places.
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the probability of getting in Black at 1st time is= 18/38= 0.4736 or 47.36% ; for the second time we have to add the 1st probability percentage to get the actual probability of getting roulette ball in black 2nd time too. so, for the 2nd time the probability is = .4736* 18/38=.4736*.4736= .2243 or 22.43%