Wheelbarrow And Bricks

Let the wheelbarrow weigh $x$ kg, and each brick weigh $y$ kg. We can form two linear equation from the pieces of information given:

$\begin{aligned} x + 16 y = 32 \\ x + 10 y = 23 \end{aligned}$

Subtracting the second equation from the first gives us $6 y = 9$ . This implies $y = \frac{3}{2}$ . Substituting this in the first equation gives us $x + 16 \times \frac{3}{2} = 32$ $\implies x = 32 - 24 = 8$

Therefore the wheel barrow weighs 8 kg.

let $W$ be the weight of the wheelbarrow alone and $B$ be the weight of one brick, then from the first statement,

$W+16B=32$ $\color{#D61F06}(1)$

from the second statement,

$W+10B=23$ $\color{#D61F06}(2)$

Subtracting $\color{#D61F06}(2)$ from $\color{#D61F06}(1)$ , we get

$6B=9$ or $B=\dfrac{9}{6}$

Substitute $B=\dfrac{9}{6}$ in any of the two given equations, in here I will substitute in $\color{#D61F06}(1)$

$W+16\left(\dfrac{9}{6}\right)=32$ $\implies$ $W=32-24=$ $\boxed{8~kgs}$

at first it was 32 kg

but, after removing 6 bricks it became 23 kg

so,6 bricks is =9 kg

or,1 brick is = 9/6 kg

or,16 bricks is =(9/6 x 16) kg=24 kg

so the weight of wheelbarrow is =(32-24)kg=8 kg

Subtract 23kg from 32kg
Answer is 9kg. Therefore we know that the weight of the six bricks was 9kg.

We can now know the total weight of all the bricks and subtract from the 32kg.
If 6 bricks = 9kg
16 bricks =?kg

If we cross multiply the above
16x9 = 144
6x? = 6?
144÷6 = 24
Therefore 24 us the total weight of bricks.
Subtract 24 from 32.

Answer is 8
Therefore weight of wheelbarrow alone is 8kg

16B + W = 32 (1)

10B + W = 23 (2)

subtract 1 from 2

6B = 9

B = 9/6 = 3-2

substitute in equation 1

16(3/2) + W = 32

W = 32 - 24

W = 8