If 2 0 2 1 2 1 is written in base 2 0 , what is the digit-sum of the converted number?
2 0 2 1 2 1 means that the number written in base 2 1
* The digit-sum of 4 3 2 = 4 + 3 + 2 = 9 . *
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2 0 2 1 2 1 = 2 ⋅ 2 1 3 + 0 ⋅ 2 1 2 + 2 ⋅ 2 1 1 + 1 ⋅ 2 1 0 = 1 8 5 2 2
1 8 5 2 2 = 2 ⋅ 2 0 3 + 6 ⋅ 2 0 2 + 8 ⋅ 2 0 1 + 5 ⋅ 2 0 0 = 2 6 8 5 2 0
2 + 6 + 8 + 5 = 2 1 .
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2 0 2 1 2 1 = 2 ⋅ 2 1 3 + 2 ⋅ 2 1 + 1
2 0 2 1 2 1 = 2 ( 2 0 + 1 ) 3 + 2 ( 2 0 + 1 ) + 1
2 0 2 1 2 1 = 2 ( 2 0 3 + 3 ⋅ 2 0 2 + 3 ⋅ 2 0 + 1 ) + 2 ⋅ 2 0 + 2 + 1
2 0 2 1 2 1 = 2 ⋅ 2 0 3 + 6 ⋅ 2 0 2 + 6 ⋅ 2 0 + 2 + 2 ⋅ 2 0 + 2 + 1
2 0 2 1 2 1 = 2 ⋅ 2 0 3 + 6 ⋅ 2 0 2 + 8 ⋅ 2 0 + 5
2 0 2 1 2 1 = 2 6 8 5 2 0
2 + 6 + 8 + 5 = 2 1