When a = 1/2, What is The Solution? (Basic)

$\begin{matrix} \frac{2a^{-1}+\frac{a^{-1}}{2}}{a}\\\\ =\frac{2\left(\frac{1}{2}\right)^{-1}+\frac{\left(\frac{1}{2}\right)^{-1}}{2}}{\left(\frac{1}{2}\right)}\\\\ =\frac{2\cdot \left(2\left(\frac{1}{2}\right)^{-1}+\frac{\left(\frac{1}{2}\right)^{-1}}{2}\right)}{1}\\\\ =2\cdot \left(2\left(2\right)+\frac{\left(2\right)}{2}\right)\\ =2\cdot \left(4+1\right)\\ =2\cdot \left(5\right)\\ =\mathbf{10} \end{matrix}$

First off, we can factorize the numerator, giving us $\frac{\frac{1}{a} * (2+\frac{1}{2}}{a}$ , which becomes $\frac{\frac{5}{2}}{a^2}$ , which is equal to $\frac{5}{2}*a^2$ . Since $\frac{1}{2}$ can become $2$ , which is the value we plug in for the variable $a$ . When we simplify, we get $\boxed{10}$ , which is our answer.