When does a quadratic equation have identical roots?

Algebra Level 1

Find the positive value of k k such that the quadratic equation 4 x 2 + k x + 9 = 0 4x^2+kx+9=0 has identical roots.


The answer is 12.

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3 solutions

Rishabh Jain
Jan 16, 2016

Eqn can be written as ( 2 x ± 3 ) 2 (2x\pm 3)^2 +(k ± \pm 12)x=0. Obviously for identical roots k ± 12 = 0 k\pm12=0 or k= ± 12 \pm12 .But since k>0 k = 12 \Rightarrow \color{limegreen}{\boxed{ k=12}}

Nihar Mahajan
Jan 16, 2016

A quadratic equation has identical roots if and only if the discriminant equals 0 0

Discriminant of 4 x 2 + k x + 9 = k 2 4 ( 4 ) ( 9 ) = k 2 144 = 0 k 2 = 144 k = ± 12 4x^2+kx+9=k^2-4(4)(9) = k^2-144=0 \Rightarrow k^2=144 \Rightarrow k=\pm 12

Hence , positive value of k = 12 \boxed{k=12} .

a x 2 + b x + c = 0 ax^2+bx+c=0
When equal roots b 2 4 a c = 0 b^2-4ac=0 .
k 2 × 4 ( 9 ) × ( 4 ) = 0 k^2-×4(9)×(4)=0
k 2 = 144 k^2=144
k = 12 \therefore k=\boxed{12}



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