Find the positive value of k such that the quadratic equation 4 x 2 + k x + 9 = 0 has identical roots.
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A quadratic equation has identical roots if and only if the discriminant equals 0
Discriminant of 4 x 2 + k x + 9 = k 2 − 4 ( 4 ) ( 9 ) = k 2 − 1 4 4 = 0 ⇒ k 2 = 1 4 4 ⇒ k = ± 1 2
Hence , positive value of k = 1 2 .
a
x
2
+
b
x
+
c
=
0
When equal roots
b
2
−
4
a
c
=
0
.
k
2
−
×
4
(
9
)
×
(
4
)
=
0
k
2
=
1
4
4
∴
k
=
1
2
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Eqn can be written as ( 2 x ± 3 ) 2 +(k ± 12)x=0. Obviously for identical roots k ± 1 2 = 0 or k= ± 1 2 .But since k>0 ⇒ k = 1 2