When solids get together

The surface area of the sphere is $4\pi r^2 = \pi$ , which tells us the radius of the sphere is $r = \frac{1}{2}$ which indicates that the diagonal of the cube is $1$ . Thus, the side of the cube is $\frac{1}{\sqrt{3}}$ . Finally, the surface area of the cube is $6\times \frac{1}{(\sqrt{3})^2} = 2$ . Keeping in mind the diagonal of the cube is the same as the diameter of the sphere.

this is easy, if the surface area of the sphere is pi, then the surface of the cube must be less than pi, and 3 is just too close to pi.