When the will is 51 Oranges

The answer is yes.

Borrow $\color{#EC7300} 3$ oranges then you will have 54 oranges, divide them as required.

$1^{st}$ person will get half $= 54/2= 27$

$2^{nd}$ person will get one-third $= 54/3 = 18$

$3^{rd}$ person will get one-ninth $= 54/9 = 6$

then the three of them will get $= 27 + 18 +6 = 51$ ---> and reminder is $\color{#EC7300} 3$ .

Assuming no others are included in the will, someone made a mistake, as the fractions do not add to 1. We reinterpret as ratios: $1/2 : 1/3 : 1/9 \qquad \Rightarrow \qquad 9 : 6 : 2$ and since $9+6+2=17$ evenly divides $51$ , we may evenly divide the oranges according to that ratio.