When you express 2020 × 2022 2020 \times 2022 in base 2021 2021

If 2020 × 2022 2020 \times 2022 is written in base 2021 2021 , what is its digit sum?

HINT: The "digit sum" of 987 987 would be 24 24 since 9 + 8 + 7 = 24 9+8+7=24 .


The answer is 4040.

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1 solution

Ossama Ismail
Dec 27, 2019

2020 × 2022 = 2020 × 202 1 1 + 2020 × 202 1 0 = ( 2020 ) ( 2020 ) 2021 2020 \times 2022 = 2020 \times 2021^1 + 2020 \times 2021^0 = (2020) (2020) _{2021}

digit-sum = 2020 + 2020 = 4040 2020+2020=4040

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