Where are you?

The vector is clearly on the III quadrant, since its axes and ordinate are both negative. We can find the angle made by this vector with the negative x-axis by using $\tan^{-1}{\frac{-2.5}{-3.5}}$ which gives $35.54^o$ . Rounded to the nearest degree gives $36^o$ . Recall that the vectors is on the III quadrant, therefore the angle made by itself with the positive x-axis is equal $180+36=216^o$

A reference from the positive x is where the angle is 0 degrees. To find the angle that the vector forms with the x axis in general, simply do inverse tangent which will result in a 35.5 degree angle formed with the negative x. Adding 180 to it gives us the whole piece interested, and rounding it up gives us 216 Degrees