Consider a circle S 1 ,
x 2 + y 2 + 1 − 2 x ( cos θ − sin θ ) − 2 y ( cos θ + sin θ ) = 0
Now, consider another circle S 2 , centred at P = ( − cos θ − sin θ , cos θ − sin θ ) such that S 1 internally touches S 2 .
Draw a pair of tangents T 1 and T 2 from P to S 1 . Let these tangents meet the circle S 2 at points A and B as shown. From a point R on S 2 , draw chords R A and R B with lengths l 1 , l 2 , respectively to S 2 .
Then, there exists a certain α such that one of
∣ ∣ ∣ ∣ ∣ cos − 1 6 l 1 + cos − 1 6 l 2 ∣ ∣ ∣ ∣ ∣ or ∣ ∣ ∣ ∣ ∣ cos − 1 6 l 1 − cos − 1 6 l 2 ∣ ∣ ∣ ∣ ∣
is equal to α regardless of the value of R . Find the value of this constant α .
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refer to first part of solution here
note that angle APR is π − 2 α and angle BPR is 3 2 π + 2 α
radius of S 2 is 3.
use cosine rule to find l 1 and l 2