The dodecahedron has 12 pentagonal faces. Therefore it has edges.
The icosahedron has 20 equilateral triangular faces. Therefore it has edges.
How many edges does a truncated icosahedron have?
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The truncated icosahedron is like the offspring of a icosahedron and a dodecahedron. (It's also the standard pattern for a soccer ball.) One way to make a truncated icosahedron is to slice each of the 12 corners of an icosahedron off to reveal 12 pentagons each surrounded by 5 hexagons. Or you can slice each of the 20 corners off a dodecahedron to reveal 20 hexagons, each touching 3 pentagons.
Either way, you get a truncated icosahedron with 20 hexagonal faces and 12 pentagonal faces. 2 2 0 × 6 + 1 2 × 5 = 9 0 is therefore the number of edges.
Why? Because the 20 hexagons have 6 × 2 0 = 1 2 0 edges among them. And the 12 pentaogns have 5 × 1 2 = 6 0 edges among them. Which naively gives 180 edges total. But each of those edges is shared by 2 polygons. Therefore, each was double-counted so in reality there are only 90 edges total.