A solid right circular cone is such that the angle between its axis and its surface is . A plane cuts through the cone at a certain angle with its axis, thus generating an elliptical base. The cone is placed on its elliptical base on a flat surface, such that the center of the ellipse coicides with the origin of an XYZ reference frame with the XY plane lying along the flat surface, and the positive Z-axis pointing upward. The XY axes orientation is such that the major axis of the elliptical base is along the X-axis and the minor axis is along the Y-axis.If the equation of the edge of the base is given by
What are the coordinates of the vertex? Assume that the vertex is located at where . Enter the value of as your answer.
Hint : Use the formulas in the solution of this problem .
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First, note that the major axis of the base lies in the same plane as the axis of the cone
and the normal to the cutting plane. Hence the axis of the cone lies in the
XZ plane. Therefore, the y-coordinate b = 0.
Next, note that, from the expressions for the semi-minor and semi-major axes
of the ellipse, we have that,
m / M = 1 − sin 2 ( θ p ) sec 2 ( θ c )
Hence,
5 3 = 1 − sin 2 ( θ p ) sec 2 ( θ c )
Since θ c = 2 0 ∘ , it is straight forward to calculate θ p to be
θ p = 4 8 . 7 4 ∘
Next, we need to find z 0 . Using the expression for the minor semi-axis (or equivalently the expression for the major semi-axis), we have
z 0 = m 1 − sin 2 ( θ p ) sec 2 ( θ c ) / ( tan θ c cos θ p )
From which,
z 0 = 3 ( 3 / 5 ) / ( tan 2 0 ∘ cos 4 8 . 7 4 ∘ ) = 7 . 4 9 9 4 4 3 2 1 1
Note that the axis of the cone intesects the XY plane at
x 0 = z 0 sin θ p tan 2 θ c / ( 1 − sin 2 ( θ p ) sec 2 ( θ c ) ) = 2 . 0 7 4 5 9 8 5 0 2
Now the vertex is now fully determined.
( a , b , c ) = ( 2 . 0 7 4 5 9 8 5 0 2 , 0 , 0 ) + 7 . 4 9 9 4 4 3 2 1 1 ( s i n ( 4 8 . 7 4 ) , 0 , c o s ( 4 8 . 7 4 ) ) = ( 7 . 7 1 2 3 , 0 , 4 . 9 4 5 5 )
Therefore, the answer is 7 . 7 1 2 3 + 0 + 4 . 9 4 5 5 = 1 2 . 6 5 7 8