( 1 1 + a 4 1 ) 3 1 + ( 1 1 + b 4 1 ) 3 1
If a and b are positive numbers such that their sum is 1, find the minimum value of the expression above.
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Same solution here
Here, since we need to find the minimum value of the sum, we can assume that the least possible value is being added to 11.
for (1/a)^4 or (1/b)^4 to be minimum, a and b have to be at their maximum possible value.
since a + b = 1, we can say that both a & b will be maximum when a = b = (1/2)
putting a = b = (1/2) in the given equation, we get 6 as the answer
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It's really strange to see that there are now(included me) 100 solvers of this problem and not a single solution.
Here, I will use Jensen's inequality since the function f ( x ) = ( 1 1 + 1 / x 4 ) 1 / 3 is convex.
Then by the inequality definition, f ( a ) + f ( b ) ≥ 2 f ( 2 a + b ) = 2 f ( 2 1 )
= 2 ( 1 1 + 2 4 ) 1 / 3 = 6