Which inequality?

Algebra Level 3

( 11 + 1 a 4 ) 1 3 + ( 11 + 1 b 4 ) 1 3 \large \left(11 + \frac1{a^4} \right)^{\dfrac13} + \left(11 + \frac1{b^4} \right)^{\dfrac13}

If a a and b b are positive numbers such that their sum is 1, find the minimum value of the expression above.


The answer is 6.

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2 solutions

Kartik Sharma
Nov 15, 2015

It's really strange to see that there are now(included me) 100 solvers of this problem and not a single solution.

Here, I will use Jensen's inequality since the function f ( x ) = ( 11 + 1 / x 4 ) 1 / 3 f(x) = \left(11+1/x^4\right)^{1/3} is convex.

Then by the inequality definition, f ( a ) + f ( b ) 2 f ( a + b 2 ) = 2 f ( 1 2 ) f(a) + f(b) \geq 2 f\left(\frac{a+b}{2}\right) = 2 f\left(\frac{1}{2}\right)

= 2 ( 11 + 2 4 ) 1 / 3 = 6 = 2 \left(11+2^4\right)^{1/3} = \boxed{6}

Same solution here

Mohammed Imran - 1 year, 2 months ago

Here, since we need to find the minimum value of the sum, we can assume that the least possible value is being added to 11.

for (1/a)^4 or (1/b)^4 to be minimum, a and b have to be at their maximum possible value.

since a + b = 1, we can say that both a & b will be maximum when a = b = (1/2)

putting a = b = (1/2) in the given equation, we get 6 as the answer

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