Tons Of Square Roots

Algebra Level 1

2 5 2 2 2 6 = ? \sqrt{\sqrt{2^5}\sqrt{2\sqrt{2\sqrt{2^6}}}} = \, ?

256 2 \sqrt{2} 4 16

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3 solutions

Zyberg Nee
Feb 13, 2016

We have an equation: 2 5 2 2 2 6 = ? \sqrt{\sqrt{2^5}\sqrt{2\sqrt{2\sqrt{2^6}}}} = ? , however, right now we will look only into a small chunk:

2 2 6 {2\sqrt{2^6}}

It is easy to notice that 2 6 \sqrt{2^6} could be simplified to: 2 3 {2^3} , which would make: 2 × 2 3 2\times{2^3} and then: 2 4 2^4 .

Now we have this: 2 5 2 2 4 = ? \sqrt{\sqrt{2^5}\sqrt{2\sqrt{2^4}}} = ?

Which simplifies to:

2 5 2 × 2 2 = 2 5 2 3 = 2 5 × 2 3 = 2 8 = 2 4 = 2 2 = 4 \sqrt{\sqrt{2^5}\sqrt{2\times2^2}} = \sqrt{\sqrt{2^5}\sqrt{2^3}} = \sqrt{\sqrt{2^5\times2^3}} = \sqrt{\sqrt{2^8}} = \sqrt{2^4} = 2^2 = \boxed{4}

I'd have left out the question marks. This = that = the other, etc.

Whitney Clark - 5 years, 3 months ago

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You are right. Somehow didn't notice that I could do this here. Must be bad habit left from doing many equations. Thank you for suggestion! :)

Zyberg NEE - 5 years, 3 months ago

2 5 2 2 2 6 = 4 2 2 2 × 8 = 4 2 2 × 4 = 4 2 × 2 2 = 4 × 2 × 2 = 16 = 4 \sqrt { \sqrt { { 2 }^{ 5 } } \sqrt { 2\sqrt { 2\sqrt { { 2 }^{ 6 } } } } } =\sqrt { 4\sqrt { 2 } \sqrt { 2\sqrt { 2\times 8 } } } =\sqrt { 4\sqrt { 2 } \sqrt { 2\times 4 } } =\sqrt { 4\sqrt { 2 } \times \quad 2\sqrt { 2 } } =\sqrt { 4\times 2\times 2 } =\sqrt { 16 } =4

Achille 'Gilles'
Feb 20, 2016

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