Which of the following is larger?

$\large A = \int^2_{-1} |x| dx = \int^0_{-1} dx + \int^2_{-1} (x) dx = \dfrac 12 +2 \implies \dfrac 52$

$\large B = \int^{2}_{-1} x dx = 2 - \dfrac 12 \implies \dfrac 32$

Hence $A > B$