Which one is stronger?

The above are 3 3 charged metal balls X , Y and Z separated by an equal distance r r on a straight line. Let F Y \lvert{F_Y}\rvert be the magnitude of the electrostatic force on Y , and let F Z \lvert{F_Z}\rvert be the magnitude of the electrostatic force on Z . What is the ratio F Y : F Z ? \lvert{F_Y}\rvert : \lvert{F_Z}\rvert?

1:2 1:1 4:1 2:1

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1 solution

Amartya Mondal
Oct 13, 2015
  • You need to be careful about the direction of electric field .

|Fy| = |[k.q^2/r^2]\times{2-1}| |Fz| = |[k.q^2/r^2]\times{1/2}| - Hence, the ratio is = 2:1

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