and respectively. What is the velocity with which the middle point of the train passes the same point? (Round your answers to nearest hundredth)
The two ends of a train moving with uniform acceleration passes a certain point with velocities
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Let S = length of the train Since this one dimensional motion we can use kinematic equations. The end point of the train with velocity of 12 kmph attains a of 15 kmph after having a displacement of the length of the s V 2 = U 2 + 2 a s 1 5 2 = 1 2 2 + 2 a s 2 ( 2 2 5 − 1 4 4 ) = a s a s = 4 0 . 5 so at the middle point, the length of the train is s / 2 V 2 = 1 4 4 + 2 a ( s / 2 ) V 2 = 1 4 4 + 4 0 . 5 V = 1 8 4 . 5 = 1 3 . 5 8 Thus this the solution sorry if this was a bit lengthy just wanted to explain it better.