Which side would you want to be in?

The two ends of a train moving with uniform acceleration passes a certain point with velocities 12 k m p h 12 kmph and 15 k m p h 15 kmph respectively. What is the velocity with which the middle point of the train passes the same point? (Round your answers to nearest hundredth)


The answer is 13.58.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Mardokay Mosazghi
Jun 27, 2014

Let S S = length of the train Since this one dimensional motion we can use kinematic equations. The end point of the train with velocity of 12 kmph attains a of 15 kmph after having a displacement of the length of the s s V 2 = U 2 + 2 a s V^2 = U^2 + 2as 1 5 2 = 1 2 2 + 2 a s 15^2=12^2+2as ( 225 144 ) 2 = a s \frac{(225-144)}{2}=as a s = 40.5 as=40.5 so at the middle point, the length of the train is s / 2 s/2 V 2 = 144 + 2 a ( s / 2 ) V^2= 144+2a(s/2) V 2 = 144 + 40.5 V^2= 144+ 40.5 V = 184.5 = 13.58 V= \sqrt{184.5} =13.58 Thus this the solution sorry if this was a bit lengthy just wanted to explain it better.

It's great but I just took the mean of 12 and 15 and I got the answer :)

satvik pandey - 6 years, 10 months ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...