In the above figure, is the centre of circle. Find .
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Let us join the point P to point Q to form a straight line P Q .
By alternate segment theorem , in the triangle P Q R , we have
∠ P Q R = 5 0 , ∠ Q P R = 6 0 .
Because the sum of angles of a triangle is 1 8 0 ∘ , then ∠ P R Q = 1 8 0 ∘ − 5 0 ∘ − 6 0 ∘ = 7 0 ∘ .