Which Triangle?

Geometry Level 4

If θ \theta is real and z 1 { z }_{ 1 } , z 2 { z }_{ 2 } are connected by z 1 2 + z 2 2 + 2 z 1 z 2 cos θ = 0 { z }_{ 1 }^{ 2 }+{ z }_{ 2 }^{ 2 }+2{ z }_{ 1 }{ z }_{ 2 }\cos { \theta } =0 , what is the triangle with vertices 0 0 , z 1 { z }_{ 1 } and z 2 { z }_{ 2 } ?

equilateral isosceles none of these right angled

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

G J
Feb 20, 2021

From z 2 2 + 2 ( z 2 cos θ ) z 1 + z 1 2 = 0 z_2^{2}+2(z_2\cos\theta)z_1+z_1^{2}=0 , we can find that z 2 = z 1 cos θ + i z 1 sin θ z_2=z_1\cos\theta + i z_1\sin\theta , hence z 2 = z 1 cos θ + i sin θ = z 1 |z_2|=|z_1||\cos\theta+i\sin\theta|=|z_1| . Therefore, the triangle with vertices 0 , z 1 0, z_1 and z 2 z_2 is an isosceles triangle.

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...