is a regular pentagon of side length 1. is an equilateral triangle with a side congruent to the pentagon's diagonal. Which triangle, red or blue, has the larger area? For extra credit, provide closed-form representations of the areas of the red and blue triangles.
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All angles are in degrees. Line segment E H divides △ A B E into two congruent right triangles. This gives the length of A B as A B = 2 ⋅ 1 ⋅ cos ( 3 6 ) = 2 cos ( 3 6 ) Using the sine rule on △ B F G , we can calculate the sides F G and B G . sin ( 6 0 ) 1 = sin ( 1 2 ) F G = sin ( 1 0 8 ) B G F G = sin ( 6 0 ) sin ( 1 2 ) B G = sin ( 6 0 ) sin ( 1 0 8 ) Since △ A B C is equilateral, B G + G C = A B . Consequently, G C = A B − B G = 2 cos ( 3 6 ) − sin ( 6 0 ) sin ( 1 0 8 ) Use the area formula A = 2 1 a b sin ( C ) on both the blue and red triangles. A ( blue ) = 2 1 ⋅ 1 ⋅ sin ( 6 0 ) sin ( 1 2 ) ⋅ sin ( 1 0 8 ) ≈ 0 . 1 1 4 A ( red ) = 2 1 ⋅ ( 2 cos ( 3 6 ) − sin ( 6 0 ) sin ( 1 0 8 ) ) 2 ⋅ sin ( 6 0 ) ≈ 0 . 1 1 7 Therefore, the red triangle has a larger area than the blue triangle.