Which will win the race?

As the image shows, O O is the center of a circle, E E is at the bottom of the circle, and A E , B E , C E , D E AE,BE,CE,DE are all smooth inclines along the circle.

Now, let's put four balls at rest at points A , B , C , D . A,B,C,D.

If whichever gets to point E E first wins the race, ignoring all the frictions, which ball will win the race?

The ball at A The ball at B The ball at C The ball at D They will get to E at the same time It depends on other conditions

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Laszlo Mihaly
Jan 18, 2018

The distance between D and E will be called s s and the distance between B and E is 2 R 2R . The angle between the two lines is α \alpha . The DBE triangle is a right triangle, therefore s = 2 R cos α s=2R \cos \alpha .

The time it takes to reach the bottom is t = 2 s / a t=\sqrt{2s/a} , where the acceleration is a = g cos α a=g \cos\alpha . Inserting s s and a a we get

t = 2 s a = 4 R cos α g cos α = 4 R g t=\sqrt{\frac{2s}{a}}=\sqrt{\frac{4R \cos \alpha}{g\cos \alpha}}= \sqrt{\frac{4R}{g}} , independent of the angle α \alpha . Therefore all of the balls will get to the bottom at the same time.

Why is this question level 1? I thought it would be assess as level 3 question.

Kelvin Hong - 3 years, 4 months ago

Log in to reply

I have just looked at it and it is now upgraded to 3.

Laszlo Mihaly - 3 years, 4 months ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...