Whisper Words of Wisdom

Level 2

Let the letters A J A \rightarrow J be the numbers from 0 0 to 9 9 , but not necessarily in this order.

What is the minimum value of A + B C + D E F + G H I J A+B \cdot C + D \cdot E \cdot F + G \cdot H \cdot I \cdot J ?


The answer is 28.

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1 solution

To minimize the function, we must be careful with where we put the "big" values. In this problem it is very simple: we can eliminate them by letting G H I J = 0 × 9 × 8 × 7 = 0 GHIJ = 0 \times 9 \times 8 \times 7 = 0 .

This leaves us with minimizing A + B C + D E F A+BC+DEF , with numbers 1 6 1 \rightarrow 6 .

Because 6 6 taking part in D E F DEF would make it really big, we'll allow A = 6 A=6 . To minimize the three-digit product, D E F DEF , let F = 1 F =1 . We are left now with B C + D E BC+DE and the numbers 2 5 2 \rightarrow 5 .

The minimum value for B C + D E BC+DE is held when the "edge" numbers (first with last, second with penult, third with antepenult, etc...) are combined. The order of the numbers will thus be ( 2 , 5 , 3 , 4 ) \; (2,5,3,4) .

We finally get that the minimum value of A + B C + D E F + G H I J A+BC+DEF+GHIJ is 28. \; \boxed{28.}

PS: Go check a very similar problem , submitted by Chung Kevin .

You should explain paragraph 3 clearer, and explain exactly why the minimum occurs when A = 6 A=6 and F = 1 F=1 . This might seem intuitive, but still requires a mathematical proof.

For example, if all we cared about was "To minimize the three-digit product, DEF", then we should let F = 1 , E = 2 , D = 3 F=1, E=2, D=3 , but this is not the case. A further explanation is required to substantiate why F = 1 F= 1 .

Calvin Lin Staff - 7 years, 5 months ago

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Thank you, Calvin. :)

Guilherme Dela Corte - 7 years, 5 months ago

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