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Algebra Level 1

3 ÷ 4 × 6 × ( 2 ) ÷ 3 + ( 4 ) ÷ ( 7 ) × 14 ( 3 ) × 3\div4\times6\times(-2)\div3+(-4)\div(-7)\times14-(-3)\times

( 6 4 × ( 2 ) ) ÷ ( 7 ) ( 3 ) × ( 2 ) ÷ ( 12 ) × ( 2 ) × 4 (6-4\times(-2))\div(-7)-(-3)\times(-2)\div(-12)\times(-2)\times4

5 × 10 × 2 ÷ ( 15 ) × 3 ( 3 ) × ( 3 × 4 3 × 4 ) -5\times10\times2\div(-15)\times3-(-3)\times(3\times4-3\times4)

÷ ( 4 ) × ( 3 ) ( 1 ) 5 × 6 ÷ 5 × 6 \div(-4)\times(-3)-(-1)-5\times6\div5\times6\

Yes that is one complete arithmetic expression.


The answer is -20.

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1 solution

Peter Michael
Dec 31, 2015

In the first set of brackets the expression is equivalent to 14, and the second 0. Replacing those expressions and eliminating all the extra pairs of brackets we can obtain this expression.

3 ÷ 4 × 6 × 2 ÷ 3 + 4 ÷ 7 × 14 3 × 14 ÷ 7 3 × 2 ÷ 12 × 2 × 4 5 × 10 × 2 ÷ 15 × 3 3 × 0 ÷ 4 × 3 1 5 × 6 ÷ 5 × 6 3\div4\times6\times-2\div3+-4\div-7\times14--3\times14\div-7--3\times-2\div-12\times-2\times4-5\times10\times2\div-15\times3--3\times0\div-4\times-3--1-5\times6\div5\times6

By using the Relocation property on the expressions that contain only multiplication and division we can simplify this expression further.

= 3 + 8 6 4 + 20 + 0 + 1 36 =-3+8-6-4+20+0+1-36

= 20 =-20

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