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Notice that if we concatenate the digit n − 1 into a repeating decimal in base n as so: 0 . ( n − 1 ) ( n − 1 ) … n , we get that its value is simply 1 .
The repeating decimal 1 in base 2 is similar to repeating decimal 9 in base 10 - so it somewhat equalizes to 1 because of rounding.
There is no rounding involved.
I'm 4 years late, but you can consider it having to be a number x between the two numbers, for the statement to be false. as we cannot find the number x (because it doesn't exist), the statement is true.
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Relevant wiki: Integer Number Bases
The number in base 2 is nothing but : 2 1 + 2 2 1 + 2 3 1 + 2 4 1 . . . . . . . . . . . . . . . . . in base 10 .That is 1