Who remembers the basics!

Geometry Level 1

What is the value of sin ⁡ 102 0 ∘ \sin 1020^\circ ?

− 3 2 \dfrac{-\sqrt{3}}2 − 1 2 \dfrac{-1}{\sqrt 2} 1 2 \dfrac 12 None

Ayushman Chahar by Ayushman Chahar , 21, India

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1 solution

Raman Saini
Jan 26, 2016

sin ⁡ 1020 ° = sin ⁡ ( 3 × 2 π − 60 ) ∘ = sin ⁡ ( − 60 ) ∘ = − sin ⁡ 6 0 ∘ = − 3 2 \sin 1020°= \sin(3\times2\pi - 60)^\circ\\=\sin(-60)^\circ=-\sin60^\circ=\boxed{\dfrac{-\sqrt{3}}{2}}

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