Who should be the winner?Part-II

The numbers from1 to 20 are written in a row. Two players, Andy and Michael take turns putting plus signs and minus signs between the numbers. When all such signs have been placed, the resulting expression is evaluated (i.e. the additions and subtractions are performed). Andy wins if the sum is even, and Michael wins if the sum is odd. Who has a winning strategy??

Andy makes the first move.

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Insufficient information to solve.Could be either of Andy and Michael. The epression will result in a fraction Michael Andy

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2 solutions

Anik Mandal
Jun 18, 2014

The parity of the result does not depend on the position of the pluses and minuses,but only on the number of odd integers in the original set of numbers.Since there are 10 odd integers to begin with,and 10 is an even number,the first player will win.

the problem with your problem was that you did not make it clear whether the no are sequentially arranged or randomly

akash deep - 6 years, 11 months ago

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They are sequentially arranged!

Sorry forgot to mention that.

Anik Mandal - 6 years, 11 months ago
Anuj Shikarkhane
Jul 22, 2014

After doing the additions and subtractions,you will get the answer as 12 which is a even number.Therefore andy has a winning strategy.

How did you get 12??

Anik Mandal - 6 years, 10 months ago

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Do it yourself.After addition and subtraction you will get 12.

Anuj Shikarkhane - 6 years, 10 months ago

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