Who Should We Choose?

Probability Level pending

In a certain Math Team, there are 18 students. The team is planning to participate in the Brilliant Math League Tournament. The tournament accepts teams of 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17 or 18 students. The teams can only be made of students in the Math Team. If one team will be assembled, how many different groups of people can be chosen to participate in the Brilliant Math League Tournament?


The answer is 262143.

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1 solution

Ashwin Padaki
Jun 7, 2015

The problem is basically asking the value of the following expression:

( 18 1 ) + ( 18 2 ) + ( 18 3 ) + ( 18 4 ) + . . . + ( 18 18 ) {18 \choose 1} + {18 \choose 2} + {18 \choose 3} + {18 \choose 4} + ... + {18 \choose 18}

This can be calculated by adding the elements in the 18 t h 18th row of Pascal's Triangle, and subtracting 1 from it (There can be no team of 0).

The sum of the elements in the n t h nth row of Pascal's Triangle can be expressed as 2 n 2^{n}

In this case, n = 18 n = 18

2 18 1 2^{18} - 1 = 262143 \boxed {262143}

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