Who would carry a weighing machine up there?

Classical Mechanics Level 1

Aareyan's weight is 76 N 76\text{ N} on the surface of Earth. What would his weight be if he is 6400 km 6400\text{ km} above the Earth's surface?

Given your answer in N \text N .

Take g = 10 ms − 2 g=10\text{ ms}^{-2} .

Sorry Aareyan if your weight is less than that.


The answer is 19.

Mehul Arora by Mehul Arora , 20, India

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1 solution

Rishabh Jain
Feb 15, 2016

Correct the spelling of 'tthe'...... ;-)
Let W,g denote the weight, acceleration due to gravity on the surface of earth and W',g' denote weight and acceleration due to gravity at R'(=2R) where R' denote the radial distance from centre of earth . W ′ W = g ′ g = R 2 ( R ′ ) 2 = 1 4 \Large \dfrac{W'}{W}= \dfrac{g'}{g}= \dfrac{R^2}{(R')^2}= \dfrac{1}{4} ∴ W ′ = W 4 = 19 \Large \therefore W'= \dfrac{W}{4}=\huge\boxed{\color{#007fff}{19}}

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Corrected, thanks :P

Good solution :)

Mehul Arora - 5 years, 4 months ago

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76N seems very less...

Aareyan Manzoor - 5 years, 4 months ago

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