Who wouldn't use a calculator?

Using the double angle formula for $\tan 2\theta$ where $\theta = tan^{-1}2$ , we obtain:

$\tan(2\tan^{-1}2)$

$= \dfrac{\tan(\tan^{-1}2)+\tan(\tan^{-1}2)}{1-\tan(\tan^{-1}2) \times \tan(\tan^{-1}2)}$

$=\dfrac{2+2}{1-2\times2}$

$=-\dfrac{4}{3}$

Hence the given expression becomes: $\dfrac{-\dfrac{4}{3}-1}{-\dfrac{4}{3}+1} = 7$

Sorry for terrible image quality. Was too lazy to actually write up solution in editor.

what i did was to take tanx=2 so tan inverse of x=2 now it becomes tan 2x -1/tan2x +1
we know the formula of tan 2x =2tanx/1-tan square x get the value of tan 2x put it in the question and bingo u get ur answer