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Calculus Level 5

lim n ( f ( n ) ) 1 / 2 n 2 \large \lim _{ n\to \infty }{ (f(n))^{ 1/2n^{ 2 } } }

Let f ( n ) f(n) denote the number of perfect matchings which cover the 2 n × 2 n 2n\times 2n square planar lattice. If the limit above can be expressed in the form A e B G / π A{ e }^{ BG/\pi } for positive integers A A and B B . Find the product A B AB .

Notation : G = n = 0 ( 1 ) n ( 2 n + 1 ) 2 0.916 \displaystyle G = \sum_{n=0}^\infty \dfrac{ (-1)^n}{(2n+1)^2} \approx 0.916 is the Catalan's constant .


The answer is 2.

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