Why C A B ? \angle CAB?

Geometry Level 2

In the given figure ABCD is a cyclic quadrilateral.The tangent to the circle at B meets DC produced at F.If E A B = 85 ° \angle EAB=85° and B F C = 50 ° \angle BFC=50° , find C A B \angle CAB .

75° 35° 10° 60° 45° 25°

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