Manufacturing Biscuits!

C = an + b

C1 = 200a + b = 55000

C2 = 500a + b = 62500

5C1 - 2C2:

1000a + 5b = 275. 10³

1000a + 2b = 125 . 10³

= 3b = 150. 10³

Then b = (150. 10³) /3 = 50. 10³

200a + b = 55000
500a + b = 62500
=> a = 25, b = 50000

C=an+b

55000 = 200a + b ....... (1) equation

62500 = 500a + b ....... (2) equation

(2) - (2)

62500 - 55000 = 500a +b - 200a - b

7500 = 300a

a = 25

put the value a = 25 on equation (1)

55000 = 200 * 25 +b

55000 = 5000 + b

b = 50000

55000=200a+b, 62500=500a+b

a=25, b=50000

Your answer should be 50,000 and not 25.

y = mx + b, the well known formula, where m is the slope. But we don't know the slope, so we need to find this out first. This is easy enough, slope is defined as rise over run, or y / x. In this case we have two points, so we find rise over run by using the formula (y - y1) = m(x - x1): (62500 - 55000) = m(500 - 200). When you find the slope, just plug it into y = mx + b, with the known values for x and y.

C=A+B ; B and A are constant

200a+b=55,000 ; 500a+b=62,500

set aside B

to simplify you'll get 300a=7500 (500a-200a=62,500-55,000)

a=7,500/300

a=25

Substitute

500(25)+b=62,500

12,500+b=62,500

b=62,500-12,500

b=50,000

C= an +b Given : Case 1: C=55000 , n= 200. So the eq'n becomes

55000= 200n +b ------> 1

Case 2: C= 62500, n=500. So the eq'n becomes

62500 = 500n +b ------->2

Solving (2-1): We get 7500=300a => n=25----> 3

Substitute 3 in 1 b=50000

C=an+b

by the conditions we get two equations,

200a+b=55000..........[1]

500a+b=62500..........[2]

By substracting equation[2] from equation[1]

we get a=25

when we substitute a=25 in equation[2]

we get b=50000

c = an +b or, an+b=c

200a+b = 55000 -------------------------------1 500a+b =62500-------------------------------2

here equation 2-1

300a = 7500 or a =25

Put value a=25 in equation no 1 200a+b = 55000 (200x25)+b=55000 5000+b=55000 b=50000

so b = 50000

(55000/200 - b)5 = (62500/500 - b)2

275000 - 5b = 125000 - 2b

275000 - 125000 = (-2b) + 5b

150000 = 3b

150000/3 = b

50000 = b

C= an+b

55000 = 200a + b;

62500 = 500a + b

solving, a=25, b=50,000

200a + b = 55000 500a + b = 62500

From here a= 25 , inserting value of a into any of above eq. we get b=50000

50,000

c=an+b 55000=200a+b........1 62500=500a+b......2 solving equation 1&2 we get b=50000

SINCE C=an+b , where

c= cost, n=no. of boxes

in case 1

n=200,c=5500

therefore55000=200a+b

200a+b-55000 = 0 ---------------------------equation i in case 2

n=5000,c=62500

62500=500a+b

500a+b-62500 =0 ----------------------------------------equation ii

solving i and ii

200a + b - 55000 = 0---------------------------i

500a + b - 62500 = 0-------------------------- ii

[-] [-] [+] = [ -]

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• 300a + 7500= 0

• 300a= - 7500 a= 7500\300

  a = 25

putting the value of a in equation 1

200a + b -55000 = 0

200 . 25 +b - 55000=0

5000+ b - 55000=0 b= 55000-5000

b=5000

$55 000 = a(200)+b ........ equation1

$62 500 = a(500)+b ........ equation2

from equation1 solve for a

a = (55 000-b)/ 200 ........ equation3

substitude equation3 into equation2

62 500 = 500((55 000-b)/ 200)+b

then solve for b

62 500 = (27 500 - 500b)/200 +b

62 500 = (27 500 000 -500b+ 200b)/200

125 00 000 = 27 500 000 - 300b

300b = 15 000 000

thereofe b = 50 000

55000=200a+b 62500=500a+b

275000=1000a+5b 125000=1000a+2b

Subtract= 150000=3b 50000=b

C = an + b

Find the Math Sentence.

C1 = 200a + b = 55000 | 5 |

C2 = 500a + b = 62500 | 2 |

Eliminate both

1000a + 5b = 275. 10³

1000a + 2b = 125 . 10³

= 3b = 150.000

=> b = 150.000/3

=> b = 50.000

C = an + b

Find the Math Sentence. C1 = 200a + b = 55000 | 5 | C2 = 500a + b = 62500 | 2 |

Eliminate both 1000a + 5b = 275. 10³ 1000a + 2b = 125 . 10³

= 3b = 150.000 => b = 150.000/3 => b = 50.000

$55000 = 200a + b$ $62500 = 500a + b$

$200a = 55000 - b$ $a = \frac{55000 - b}{200}$ $62500 = \frac{27500000 - 500b}{200} + b$ $62500 - b = 137500 - 2.5b$ $1.5b = 75000$ $b = 50000$

c1=200a+b=55000------------ (1) c2=500a+b=62500------------(2) (2)-(1) a=25 b=50000

C=an+b

55000=a*200+b

62500=a*500+b

Solving these we get

a=25

substituting this on above we get

b=50000

so the answer is 50000

c=an+b 55000=200a+b.........(i) 62500=500a+b.........(ii) subtractin i from ii we get 7500=300a a=25 put in (i) we get b=50000

200a+b=55000 500a+b=62500 a=25 so b=50000

c=an+b 55000=200a+b equation 1 62500=500a+b equation 2 multiply equation 1 with 2.5 and then get eqution 3 137500=5ooa+b eqution 3 and subtract equation 3 with equation 2 137500=500a+b 62500=500a+b and get 75000=1.5b and b=75000/1.5 and your answer is b=50000

C = an + b

   55000 = 200n + b   
   b = 55000 - 200n         ------------> equation 1

    62500 = 500n + b         ------------> equation 2

to find (b) ,

first, solve for (n) -------- using the 2nd equation

62500 = 500n + b ------------>then, substitute the value of (b) in the equation 1 to equation 2

                                                         (equation 1 : b = 55000- 200n )

     62500 = 500n + 55000 -200n

     62500 - 55000 = 500n - 200n

     7500 = 300n

      n = 7500/300

      n = 25

now, we can solve for (b)

eq. 1
b = 55000 - 200n

      b = 55000 - 200(25)                                         

      b = 55000 - 5000

eq. 2 62500 = 500n +b

      b = 62500 - 500(25)

      b = 62500 - 12500

      b = 50000

therefore, B = 50000