Why Calculus though?

Calculus Level 5

k = 1 n x k J k = 1 n 1 x k J \displaystyle \sum_{k=1}^{n} x_k^J \le \sum_{k=1}^n \dfrac{1}{x_k^J}

Given that J = 3 2 J=\frac{3}{2} and that x 1 , x 2 , , x n x_1,x_2, \ldots,x_n are positive reals whose sum is n n , find the largest integer n n such that the inequality above always holds true.

If you think all positive integers n n make the inequality hold true, enter 0 as your answer.


Original

Bonus: Solve this question when J = 1.15982 J=1.15982


The answer is 36.

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