Why calculus?

Calculus Level 3

For a unit circle centered at ( 0 , 0 ) (0,0) , we draw n n equally spaced chords parallel to the y y -axis between x = 1 x = -1 and x = 1 x = 1 . What is the limit of the average length of these chords as we let n n tend to infinity?

Details and assumptions:

  • Any argument of a trigonometric function in the answer choices is in radians.
2 \sqrt{2} 1 + sin ( 2 ) 2 1 + \dfrac{\sin(2)}{2} 1 π 2 \dfrac{\pi}{2} π 3 \dfrac{\pi}{3}

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Yash Ghaghada
Nov 18, 2017

Actually it don't need calculus

The area of circle is (π)r^2, which can also be written as

{ the average length of chord. (∆)}×(the length of base ) here r=1

π = ∆×2 =≥ ∆=π/2

This is incoherent nonsense.

Hobart Pao - 3 years, 6 months ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...