What is the maximum number of intersection points of 4 circles and 4 parabolas?
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This is a very simple question.
It has three cases:
C a s e − I : Two circles cut each other.
The maximum number of intersection points is 2 .
Therefore, ( 2 4 ) × 2 = 1 2 [ Since we have to select any two circles and then each such pair have two intersection points]
C a s e − I I : Two parabolas cut each other.
The maximum number of intersection points is 4 .
Therefore, ( 2 4 ) × 4 = 2 4 [ Since we have to select any two parabolas and then each such pair have four intersection points]
C a s e − I I I : One circle and on parabola cut each other.
The maximum number of intersection points is 2 .
Therefore, ( 1 4 ) × ( 1 4 ) × 4 = 6 4 [ Since we have to select any one circle and one parabola and then each such pair have four intersection points]
Thus , total number of intersection points is 1 2 + 2 4 + 6 4 = 1 0 0