I have a pipe, which can fill water in a beaker in 6 hours. But, there is a hole at the bottom of the beaker that can empty the same beaker which is full of water in 8 hours.
How much time (in hours) will the pipe take to fill the beaker. If the hole is also opened?
Assumptions: The beaker is to be assumed empty when the pipe and hole are opened to fill and empty it respectively. Water is flowing out at a constant rate, regardless of the depth of the water.
This question is part of the set All-Zebra
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
The pipe fill 6 1 of beaker in 1 hour.
The hole empty 8 1 of beaker in 1 hour.
The net effect is 6 1 − 8 1 = + 2 4 1 per hour.
It takes 2 4 hour to fill the beaker if both pipe and hole are open.