Why was the Calculator Invented?

A = 2.00 2 6 A = 2.002^{6}

Find the sum of all digits of A A .


The answer is 91.

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1 solution

Mateo Reddy
Jul 9, 2016

It makes it easier to deal with ( 2 + ( 2 × 1 0 3 ) ) 6 (2+(2\times 10^{-3}))^{6}

Using binomial expansion

( 2 + ( 2 × 1 0 3 ) ) 6 = ( 6 0 ) ( 2 ) 6 ( 2 × 1 0 3 ) 0 + ( 6 1 ) ( 2 ) 5 ( 2 × 1 0 3 ) 1 + ( 6 2 ) ( 2 ) 4 ( 2 × 1 0 3 ) 2 + ( 6 3 ) ( 2 ) 3 ( 2 × 1 0 3 ) 3 + ( 6 4 ) ( 2 ) 2 ( 2 × 1 0 3 ) 4 + ( 6 5 ) ( 2 ) 1 ( 2 × 1 0 3 ) 5 + ( 6 6 ) ( 2 ) 0 ( 2 × 1 0 3 ) 6 (2+(2\times 10^{-3}))^{6}=\binom{6}{0}(2)^{6}(2\times 10^{-3})^{0}+\binom{6}{1}(2)^{5}(2\times 10^{-3})^{1}+\binom{6}{2}(2)^{4}(2\times 10^{-3})^{2}+\binom{6}{3}(2)^{3}(2\times 10^{-3})^{3}+\binom{6}{4}(2)^{2}(2\times 10^{-3})^{4}+\binom{6}{5}(2)^{1}(2\times 10^{-3})^{5}+\binom{6}{6}(2)^{0}(2\times 10^{-3})^{6}

= 64 + 6 ( 32 ) ( 2 × 1 0 3 ) + 15 ( 16 ) ( 4 × 1 0 6 ) + 20 ( 8 ) ( 8 × 1 0 9 ) + 15 ( 4 ) ( 16 × 1 0 12 ) + 6 ( 2 ) ( 32 × 1 0 15 ) + 64 × 1 0 18 =64+6(32)(2\times 10^{-3})+15(16)(4\times 10^{-6})+20(8)(8\times 10^{-9})+15(4)(16\times 10^{-12})+6(2)(32\times 10^{-15})+64\times 10^{-18}

= 64 + 0.384 + 0.000 960 + 0.000 001 280 + 0.000 000 000 960 + 0.000 000 000 000 384 + 0.000 000 000 000 000 064 =64+0.384+0.000\,960+0.000\,001\,280+0.000\,000\,000\,960+0.000\,000\,000\,000\,384+0.000\,000\,000\,000\,000\,064

= 64.384 961 280 960 384 064 = A =64.384\,961\,280\,960\,384\,064=A

Adding the digits of A A

6 + 4 + 3 + 8 + 4 + 9 + 6 + 1 + 2 + 8 + 0 + 9 + 6 + 0 + 3 + 8 + 4 + 0 + 6 + 4 = 91 6+4+3+8+4+9+6+1+2+8+0+9+6+0+3+8+4+0+6+4= \mathbf{91}

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