Find the sum of all digits of .
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It makes it easier to deal with ( 2 + ( 2 × 1 0 − 3 ) ) 6
Using binomial expansion
( 2 + ( 2 × 1 0 − 3 ) ) 6 = ( 0 6 ) ( 2 ) 6 ( 2 × 1 0 − 3 ) 0 + ( 1 6 ) ( 2 ) 5 ( 2 × 1 0 − 3 ) 1 + ( 2 6 ) ( 2 ) 4 ( 2 × 1 0 − 3 ) 2 + ( 3 6 ) ( 2 ) 3 ( 2 × 1 0 − 3 ) 3 + ( 4 6 ) ( 2 ) 2 ( 2 × 1 0 − 3 ) 4 + ( 5 6 ) ( 2 ) 1 ( 2 × 1 0 − 3 ) 5 + ( 6 6 ) ( 2 ) 0 ( 2 × 1 0 − 3 ) 6
= 6 4 + 6 ( 3 2 ) ( 2 × 1 0 − 3 ) + 1 5 ( 1 6 ) ( 4 × 1 0 − 6 ) + 2 0 ( 8 ) ( 8 × 1 0 − 9 ) + 1 5 ( 4 ) ( 1 6 × 1 0 − 1 2 ) + 6 ( 2 ) ( 3 2 × 1 0 − 1 5 ) + 6 4 × 1 0 − 1 8
= 6 4 + 0 . 3 8 4 + 0 . 0 0 0 9 6 0 + 0 . 0 0 0 0 0 1 2 8 0 + 0 . 0 0 0 0 0 0 0 0 0 9 6 0 + 0 . 0 0 0 0 0 0 0 0 0 0 0 0 3 8 4 + 0 . 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 6 4
= 6 4 . 3 8 4 9 6 1 2 8 0 9 6 0 3 8 4 0 6 4 = A
Adding the digits of A
6 + 4 + 3 + 8 + 4 + 9 + 6 + 1 + 2 + 8 + 0 + 9 + 6 + 0 + 3 + 8 + 4 + 0 + 6 + 4 = 9 1