1 2 3 4 5 6 7 8 9 = p 1 q 1 ⋅ p 2 q 2 ⋅ p 3 q 3 ⋯ p n q n Let p 1 , p 2 , … , p n be distinct prime numbers satisfying the equation above, and q 1 , q 2 , … , q n be positive integers.
Find p 1 + p 2 + ⋯ + p n .
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1 2 3 4 5 6 7 8 9 = 3 2 × 3 6 0 7 × 3 8 0 3 , so 3 + 3 6 0 7 + 3 8 0 3 = 7 4 1 3 .