Will factorization work?

123456789 = p 1 q 1 p 2 q 2 p 3 q 3 p n q n 123456789 =p_1^{q_1} \cdot p_2^{q_2} \cdot p_3^{q_3} \cdots p_n^{q_n} Let p 1 , p 2 , , p n p_1, p_2, \ldots , p_n be distinct prime numbers satisfying the equation above, and q 1 , q 2 , , q n q_1, q_2, \ldots, q_n be positive integers.

Find p 1 + p 2 + + p n p_1 +p_2 + \cdots + p_n .


The answer is 7413.

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1 solution

Zico Quintina
Jul 15, 2018

123456789 = 3 2 × 3607 × 3803 123456789 = 3^2 \times 3607 \times 3803 , so 3 + 3607 + 3803 = 7413 3 + 3607 + 3803 = \boxed{7413} .

How did you get 3607 and 3803?Did you wrote a computer program?

X X - 2 years, 10 months ago

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