It's a long journey

Two points A and B situated 10m apart. A particle starts at A and covers half of the distance between itself and B every one second.Find the average velocity (in 10 m/s) of his journey from A to B

1 10 \dfrac{1}{10} l n 4 ln 4 None of these 0 ( 1 2 ) 4 \left(\dfrac{1}{2}\right)^4 ln 2 \ln 2

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1 solution

Akhil Bansal
Dec 17, 2015

At t = 0 t=0 , separation = 10 m

At t = 1 s t=1s , separation = 5 m

At t = 2 s t=2s , seperation = 2.5 m

At t = 3 s t=3s , seperation = 1.25 m

\quad \ \ \vdots \quad \quad\quad \quad \ \quad \vdots

At t = t = \infty , seperation = 0 m

Average Velocity = Total Displacement Total Time = 10 = 0 \text{Average Velocity} = \dfrac{\text{Total Displacement}}{\text{Total Time}} = \dfrac{10}{\infty} = 0

Moderator note:

Ah yes, if you procrastinate and only do half of the work each day, then you will never ever get done.

What if the distance between A and B is also infinite? Grin.

Calvin Lin Staff - 5 years, 5 months ago

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Then,we have to apply limits.. \dfrac{\infty}{\infty} form.. lol..

Akhil Bansal - 5 years, 5 months ago

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