Will the ice crack?

Ice has formed on a shallow pond and a steady state has been reached, with the air (above the ice) at 5 o C \displaystyle -5^o C , and the bottom of the pond at 4 o C \displaystyle 4^o C .

If the total depth of ice + water \displaystyle \text{ice + water} is 1.4 m \displaystyle 1.4m , then find the thickness of the ice (in m ) layer on the pond.

Details and Assumptions:
\bullet K i c e = 0.4 cal / m o C \displaystyle K_{ice} = 0.4 \text{cal}/m-^oC
\bullet K w a t e r = 0.125 cal / m o C \displaystyle K_{water} = 0.125 \text{cal}/m-^oC , where K \displaystyle K denotes the thermal conductivity.

Note: This problem appeared in our AITS (All India Test Series)


The answer is 1.12.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

3 solutions

Pratik Shastri
May 29, 2014

At the point where the ice meets the water, T = 0 o C T=0^oC

Now, let d d be the thickness of the ice formed.

In the equilibrium condition, the d Q d t \frac{dQ}{dt} from ice to water equals that from water to ice.

So,

K i c e A 4 d = K w a t e r A 5 1.4 d \frac {K_{ice}*A*4}{d}= \frac{K_{water}*A*5}{1.4-d}

Plugging the values and solving for d, we get

d = 1.12 m \boxed {d=1.12m}

Maybe the equation should be K(ice) A 5/d=K(water)*4/d Plaese reply Like this answer is 0.4

Aishwary Omkar - 6 years, 8 months ago

can know which AITS is this from??

Abhranil Das - 4 years, 1 month ago
Chew-Seong Cheong
May 27, 2014

Let the thickness of ice be x. It should be noted that the temperature at the bottom of the ice is 0 degree Celcius. At equilibrium, the heat Q conducted through the (1.4 - x) m thick layer of water is same as that through the x m thick layer of ice.

Therefore, Q = 0.125 (4-0)/(1.4 - x) = 0.4 (0 -(-5))/x

And this gives: 2.5x = 2.8 and x = 1.12

Murlidhar Sharma
May 9, 2014

Equating KA\Delta T/L for ice and water and putting the temperature of junction of ice and water as 0 we get the answer.

Isn't the thickness of the ice 0.28 m (=1.4 - 1.12)?

Sungil Cho - 7 years ago

Log in to reply

No.... why?

Md Zuhair - 3 years, 4 months ago

it was 1.12 i think u made a small mistake

Murlidhar Sharma - 7 years ago

From which AITS this problem was?

Riya chauahan - 7 years ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...