Will you integrate it 2015 times? - II

Calculus Level 3

A function f : R R f : \mathbb{R} \rightarrow \mathbb{R} is differentiated 2015 times to get g ( x ) = d 2015 d x 2015 [ f ( x ) ] g(x) = \dfrac{ d^{2015} }{dx^{2015} } \big[ f(x) \big] .

True or False

If g ( x ) = 0 g(x) = 0 for all values of x x , then f ( x ) = 0 f(x) = 0 has finitely many solutions.


This problem is part of the set - Will you integrate it 2015 times? .
True False

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1 solution

Pranshu Gaba
Nov 11, 2015

Let f ( n ) ( x ) f ^{ (n) } (x) denote the n n th derivative of f ( x ) f(x) with respect to x x .

We are given that g ( x ) = f ( 2015 ) ( x ) = 0 g(x) = f^{(2015)} (x) = 0 for all x x . After integrating 2015 2015 times, we get

f ( x ) = c 1 x 2014 + c 2 x 2013 + c 3 x 2012 + + c 2014 x + c 2015 f(x) = c_{1} x^{2014} + c_{2} x^{2013} + c_{3} x^{2012} + \cdots + c_{2014} x + c_{2015}

Here, c i c_{i} 's can be any real numbers. Note that if all the c i c_{i} 's are zero, then f ( x ) = 0 f(x) = 0 for all x x , and it will have infinitely many solutions. We have found a counterexample to the statement in the problem, therefore the statement is False \boxed {\text{False} } . _\square

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