Will you integrate it 2015 times? - XI

Calculus Level 4

A function f : R R f : \mathbb{R} \rightarrow \mathbb{R} is differentiated 2015 times to get g ( x ) = d 2015 d x 2015 [ f ( x ) ] g(x) = \dfrac{ d^{2015} }{dx^{2015} } \big[ f(x) \big] .

If g ( x ) g(x) is a periodic function with a fundamental period p p , then what can be said about f ( x ) f(x) ?
Choose the most appropriate option.


This problem is part of the set - Will you integrate it 2015 times? .
f ( x ) f(x) is periodic, with fundamental period greater than or equal to p p . f ( x ) f(x) is not necessarily periodic. f ( x ) f(x) is periodic, with fundamental period equal to p p . f ( x ) f(x) is periodic, with fundamental period less than or equal to p p . f ( x ) f(x) is periodic, with fundamental period less than, greater than or equal to p p .

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1 solution

Pranshu Gaba
Nov 12, 2015

Consider the function g ( x ) = sin x g(x) = \sin x for all x x . It is periodic with a fundamental period of 2 π 2\pi . After integrating it 2015 2015 times, we get

f ( x ) = cos x + c 1 x 2014 + c 2 x 2013 + c 3 x 2012 + + c 2014 x + c 2015 f(x) = -\cos x + c_{1} x^{2014} + c_{2} x^{2013} + c_{3} x^{2012} + \cdots + c_{2014} x + c_{2015}

Here, c i c_{i} 's are any real numbers. If we choose all of c 1 , c 2 , , c 2014 c_{1}, c_{2}, \ldots, c_{2014} to be zero, then f ( x ) f(x) is periodic with fundamental period 2 π 2\pi . Otherwise , f ( x ) f(x) will not be periodic. This means f ( x ) f(x) is not necessarily periodic. _\square

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