There are 7 adults, 5 children and 4 babies. In randomly choosing 12 people, what is the probability that 4 adults, 4 children and 4 babies are chosen?
A: (7P4 x 5P4 x 4P4)÷16C4
B: (7C4 x 5C4 x 4C4)÷16C12
C: (7C4 + 5C4 +4C4)÷16C12
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
probability= number of desired÷ total possible number
we need to choose 4 adults from 7 adults, it's a combination question. So we should write it as 7C4.
Then use 7C4 to multiplied by 5C4 and 4C4.
total possible number is 16C12. 16 is come from (7+5+4), we need to choose (4+4+4) people from total 16 people.