The electric field between the plates of a parallel-plate capacitor of capacitance drops to of its initial value in when the plates are connected by a thin wire.
Find the resistance of the wire.
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The discharge characteristic of a capacitor as formulated below has been produced by considering a series R C circuit in which a capacitor at full charge is made to discharge at time, t = 0 when the plates are connected through a resistor R . We need to find this R .
E = E 0 e − t / R C ... (i)
E = 3 E 0 1 , C = 2 . 0 μ F and t = 4 . 4 μ s are given. Using these in (i), we get:
3 E 0 1 = E 0 e − 4 . 4 / 2 R
⟹ l n ( 3 1 ) = e − 4 . 4 / 2 R
⟹ − 1 . 1 = − 2 R 4 . 4
⟹ R = 2 Ω (rounded off)